[2x+3][3x+1]=11x+3

Solution for [2x+3][3x+1]=11x+3 equation:

Simplifying
[2x + 3][3x + 1] = 11x + 3

Reorder the terms:
[3 + 2x][3x + 1] = 11x + 3

Reorder the terms:
[3 + 2x][1 + 3x] = 11x + 3

Multiply [3 + 2x] * [1 + 3x]
[3[1 + 3x] + 2x * [1 + 3x]] = 11x + 3
[[1 * 3 + 3x * 3] + 2x * [1 + 3x]] = 11x + 3
[[3 + 9x] + 2x * [1 + 3x]] = 11x + 3
[3 + 9x + [1 * 2x + 3x * 2x]] = 11x + 3
[3 + 9x + [2x + 6x2]] = 11x + 3

Combine like terms: 9x + 2x = 11x
[3 + 11x + 6x2] = 11x + 3

Reorder the terms:
3 + 11x + 6x2 = 3 + 11x

Add '-3' to each side of the equation.
3 + 11x + -3 + 6x2 = 3 + -3 + 11x

Reorder the terms:
3 + -3 + 11x + 6x2 = 3 + -3 + 11x

Combine like terms: 3 + -3 = 0
0 + 11x + 6x2 = 3 + -3 + 11x
11x + 6x2 = 3 + -3 + 11x

Combine like terms: 3 + -3 = 0
11x + 6x2 = 0 + 11x
11x + 6x2 = 11x

Add '-11x' to each side of the equation.
11x + -11x + 6x2 = 11x + -11x

Combine like terms: 11x + -11x = 0
0 + 6x2 = 11x + -11x
6x2 = 11x + -11x

Combine like terms: 11x + -11x = 0
6x2 = 0

Solving
6x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.
x2 = 0

Simplifying
x2 = 0

Take the square root of each side:
x = {0}